8r^2-8=0

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Solution for 8r^2-8=0 equation: 



8r^2-8=0

a = 8; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·8·(-8)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$


$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*8}=\frac{-16}{16}
=-1
$


$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*8}=\frac{16}{16}
=1
$

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